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fix: typo error (#20)

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Rholais Lii
2018-04-14 19:22:12 +08:00
committed by Ou Changkun
parent 622b5b4335
commit cba5c6c652
1 changed files with 2 additions and 2 deletions
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4
book/zh-cn/02-usability.md
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@@ -375,7 +375,7 @@ decltype(x+y) z;
if (std::is_same<decltype(x), int>::value) if (std::is_same<decltype(x), int>::value)
std::cout << "type x == int" << std::endl; std::cout << "type x == int" << std::endl;
if (std::is_same<decltype(x), float>::value) if (std::is_same<decltype(x), float>::value)
std::cout << "type z == float" << std::endl; std::cout << "type x == float" << std::endl;
if (std::is_same<decltype(x), decltype(z)>::value) if (std::is_same<decltype(x), decltype(z)>::value)
std::cout << "type z == type x" << std::endl; std::cout << "type z == type x" << std::endl;
``` ```
@@ -389,7 +389,7 @@ type z == type x
### 尾返回类型推导 ### 尾返回类型推导
你可能会思考，在介绍 `auto`时，我们已经提过类型推导不能用于函数形参，那么`auto` 能不能用于推导函数的返回类型呢？还是考虑一个加法函数的例子，在传统 C++ 中我们必须这么写： 你可能会思考，在介绍 `auto`时，我们已经提过类型推导不能用于函数形参，那么 `auto` 能不能用于推导函数的返回类型呢？还是考虑一个加法函数的例子，在传统 C++ 中我们必须这么写：
```cpp ```cpp
template<typename R, typename T, typename U> template<typename R, typename T, typename U>