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book: reword generic lambda

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Fixes #242
This commit is contained in:
Changkun Ou
2022-07-17 15:08:18 +02:00
parent e50e3c64f2
commit 2e9eed9ecc
2 changed files with 9 additions and 15 deletions
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book/en-us/03-runtime.md
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@@ -126,13 +126,9 @@ initialize it in the expression.
In the previous section, we mentioned that the `auto` keyword cannot be used
in the parameter list because it would conflict with the functionality of the template.
But Lambda expressions are not ordinary functions, so Lambda expressions are not templated.
This has caused us some trouble: the parameter table cannot be generalized,
and the parameter table type must be clarified.
Fortunately, this trouble only exists in C++11, starting with C++14.
The formal parameters of the Lambda function can use the `auto` keyword
to generate generic meanings:
But lambda expressions are not regular functions, without further specification on the typed parameter list, lambda expressions cannot utilize templates. Fortunately, this trouble
only exists in C++11, starting with C++14. The formal parameters of the lambda function
can use the `auto` keyword to utilize template generics:
```cpp
void lambda_generic() {
@@ -221,7 +217,7 @@ int foo(int a, int b, int c) {
;
}
int main() {
// bind parameter 1, 2 on function foo,
// bind parameter 1, 2 on function foo,
// and use std::placeholders::_1 as placeholder for the first parameter.
auto bindFoo = std::bind(foo, std::placeholders::_1, 1,2);
// when call bindFoo, we only need one param left
@@ -483,8 +479,8 @@ int main() {
// "str: Hello world."
std::cout << "str: " << str << std::endl;
// use push_back(const T&&),
// no copy the string will be moved to vector,
// use push_back(const T&&),
// no copy the string will be moved to vector,
// and therefore std::move can reduce copy cost
v.push_back(std::move(str));
// str is empty now