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Remove claims that "constexpr functions are pure" (#1307)
F.4 and F.8 made this erroneous claim as parts of notes which are entirely removed.
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@@ -2601,25 +2601,6 @@ it just guarantees that the function can be evaluated at compile time for consta
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##### Note
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##### Note
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`constexpr` functions are pure: they can have no side effects.
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int dcount = 0;
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constexpr int double(int v)
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{
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++dcount; // error: attempted side effect from constexpr function
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return v + v;
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}
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This is usually a very good thing.
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When given a non-constant argument, a `constexpr` function can throw.
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If you consider exiting by throwing a side effect, a `constexpr` function isn't completely pure;
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if not, this is not an issue.
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??? A question for the committee: can a constructor for an exception thrown by a `constexpr` function modify state?
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"No" would be a nice answer that matches most practice.
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##### Note
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Don't try to make all functions `constexpr`.
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Don't try to make all functions `constexpr`.
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Most computation is best done at run time.
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Most computation is best done at run time.
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@@ -2795,16 +2776,6 @@ Pure functions are easier to reason about, sometimes easier to optimize (and eve
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template<class T>
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template<class T>
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auto square(T t) { return t * t; }
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auto square(T t) { return t * t; }
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##### Note
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`constexpr` functions are pure.
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When given a non-constant argument, a `constexpr` function can throw.
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If you consider exiting by throwing a side effect, a `constexpr` function isn't completely pure;
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if not, this is not an issue.
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??? A question for the committee: can a constructor for an exception thrown by a `constexpr` function modify state?
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"No" would be a nice answer that matches most practice.
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##### Enforcement
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##### Enforcement
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Not possible.
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Not possible.
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