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Added s suffix to string literal

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As written, the type for "Hamlet" without the `s` suffix will be deduced to `const char*` instead of the intended `std::string`, see example earlier for auto deduced `std::string` for "Ophelia"s with the `s` suffix.
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Arturo Martín-de-Nicolás
2016-08-24 16:01:48 -05:00
committed by GitHub
parent 1ddd9cdb7a
commit d01675876f
1 changed files with 1 additions and 1 deletions
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CppCoreGuidelines.md
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@@ -14134,7 +14134,7 @@ Note that C++17 will make this rule redundant by allowing the template arguments
[Template parameter deduction for constructors (Rev. 3)](http://www.open-std.org/jtc1/sc22/wg21/docs/papers/2016/p0091r1.html). [Template parameter deduction for constructors (Rev. 3)](http://www.open-std.org/jtc1/sc22/wg21/docs/papers/2016/p0091r1.html).
For example: For example:
tuple t1 = {1, "Hamlet", 3.14}; // deduced: tuple<int, string, double> tuple t1 = {1, "Hamlet"s, 3.14}; // deduced: tuple<int, string, double>
##### Enforcement ##### Enforcement